Causes of Health Problem Essay

1449/1 Mathematics Daily news 1 March. / ov. 2011 you ¼ hours

JABATA PELAJARA MELAKA

PEPERIKSAA SELARAS AKHIR TAHU TI GKATA four, 2011

MATH

Paper you One hour and fifteen minutes

DO OT OPE THIS QUESTIO PAPER U TIL YOU ARE ADVISED TO DO SO 1 ) This query paper includes 40 questions. 2 . Solution all questions. several. Answer every question simply by blackening the proper space on the answer linen. 4. Blacken only one space for each question. 5. If you would like change your answer, erase the blackened tag that you have completed. Then blacken the space intended for the new answer. 6. The diagrams inside the questions offered are not attracted to scale unless stated. 7. A list of formulae is offered on web pages 2 and 3. 8. You may make use of a non-programmable technological calculator.

This question conventional paper consists of twenty-eight printed web pages

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a couple of MATHEMATICAL FORMULAE

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The subsequent formulae can be helpful in answering the questions. The signs given will be the ones frequently used. RELATIO T 1 2 3 four a meters × a n = a m+ n a m ÷ a n = a m−n

(a m ) n sama dengan a mn

A −1 =

you  d − b   ad − bc  − c a   

n( A) n (S )

5 6

several

P ( A) =

P ( A' ) = you − P( A)

Distance = ( x two − x1 ) two + ( y two − y1 ) a couple of

8

 x1 + x two y1 + y a couple of ,  Midpoint, ( x, sumado a ) sama dengan  a couple of   2 Typical speed sama dengan

9

range travelled time taken

15

Mean = Mean sama dengan

sum of data number of data

11 doze

sum of(class mark × frequency) sum of frequencie s

Pythagoras Theorem c2 = a2 + b2

13

m=

y two − y1 x 2 − x1

14

m=−

y − int ercept x − int ercept

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3

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SHAPES A D SPACE

1 a couple of 3 four 5 6th 7 almost 8

Area of trapezium =

1 × total of parallel sides × height 2

Circumference of circle sama dengan πd = 2πr

two Area of circle = πr

Curved surface area of cylinder = 2πrh

2 Surface area of ball = 4πr

Volume of correct prism = cross sectional area × length Volume of cylinder = πr 2h Volume of cone = one particular 2 πr h several 4 3 πr three or more 1 × base area × level 3

9

Volume of world =

twelve 11 doze

Volume of correct pyramid sama dengan

Sum of interior aspects of a polygon = (n – 2) × 180º arc span angle subtended at centre = area of group 360 u area of sector angle subtended at center = area of circle fish hunter 360 o Scale factor, k = PA' PA

13

14 15

Area of image = k2 × part of object

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4 Answer your concerns.

Jawab sepenuhnya soalan.

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1

Circular off several. 028 appropriate to three significant figures. Bundarkan 3. 028 betul pada tiga angka bererti. A 3. 02 B a few. 03 C 3. 020 D a few. 030 Considering the fact that 0. 000 078 sama dengan m by 10n, wherever m x 10n is a number in standard type. State the significance of m and of n. Diberi bahawa 0. 000 078 = m x 10n, dengan keadaan m times 10n adalah nombor di dalam bentuk piawai. yatakan nilai m serta nilai n. A meters = six. 8, d = − 5 M m = 7. almost 8, n sama dengan 5 C m = 78, d = − 6 G m sama dengan 78, d = 6 0. 078 = 2 . 6 × 10 five A a few x 10-3 B three or more x 10-4 C a few x 10-6 D three or more x 10-7

2

three or more

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five

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The entire population of Malaysia in the year 2010 is 26. thirty seven million. It really is given that the number of people who are 60 years of age and above is 4. 2% of the total population. Compute the number of people who find themselves below 6 decades of age. [1 million = 106] Besarnya populasi Malaysia dalam tahun 2010 ialah 26. thirty seven juta. Diberi bahawa bilangan orang yang berumur 60 tahun lalu ke arah adalah 4. 2% daripada jumlah populasi. Hitung bilangan orang yang berumur dalam bawah 70 tahun. [ I juta = 106 ] A ONE. 11 back button 106 M 1 . 11 x 107 C 2 . 53 times 106 M 2 . 53 x 107

5

Examine: ilaikan: almost 8. 32 times 10-5 – 7. 6 x 10-6.

A W C D 6

six. 56 x 10-6 eight. 56 times 10-6 7. 56 x 10-5 eight. 56 back button 10-5

(2x – y)2 – x(x + y) = A 3x2 – y2 – 3xy M 3x2 & y2 – 3xy C 3x2 – y2 – 5xy G 3x2 + y2 – 5xy

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6

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7 In Diagram 7, HIJKLM is a regular hexagon. JKLO is a rhombus and JL is the oblicuo of the rhombus....



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